[fpc-pascal] Comparing version numbers

[A.J. Venter]

Actually I found my answer just now after asking a friend who is a debian 
user.
Turns out debian documents the pseudocode for their method in the manpages.

So I am just busy translating the pseudo to pascal now.

1. take any initial string of non-digits from each, remove, and compare 
ASCIIbetically.
If there's a difference, terminate. If not:
2. Take any initial string of digits from each, remove, and compare 
numerically.
If there's a difference, terminate. If not, goto 1.

(Oh and I'm using while, not goto :p )

A.J.

On Friday 02 June 2006 23:11, Vincent Snijders wrote:
> A.J. Venter wrote:
> > So the question is:
> > 1) does somebody HAVE an algorithm for this already ?
> > 2) If not, can somebody give me a hint about what approach to take ?
>
> Split the version string in several numbers:
> version := '4.0.12';
> major := 4
> minor := 0;
> patch := 12;
>
> versionnumber := major * 10000 + minor * 100 + patch
>
> then you can numerically compare version numbers.
>
> the 100 (a) and 10000 (b) can be adjusted for your needs.
>
> a must be bigger than the max number of patches
> b must be bigger that the max numer of patches times the max numer of
> minor versions.
>
> So this algorithm can not 4.194.299
>
> Vincent
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-- 
"there's nothing as inspirational for a hacker as a cat obscuring a bug 
by sitting in front of the monitor" - Boudewijn Rempt
A.J. Venter
Chief Software Architect
OpenLab International
www.getopenlab.com
www.silentcoder.co.za
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