[fpc-pascal] evaluation of set constant
Jonas Maebe
jonas.maebe at elis.ugent.be
Wed Dec 22 14:50:21 CET 2010
On 22 Dec 2010, at 14:15, Torsten Bonde Christiansen wrote:
> Is it possible to create a constant of a set that is based on an
> evaluation of other constants? (using fpc 2.4.2)
>
> A basic case could look like this:
>
> type
> TMyType = (a, b, c ,d);
> TMyTypes = set of TMyTypes;
>
> const
> SetX: TMyTypes = (a, b);
> SetY: TMyTypes = (c, d);
These definitions should not compile, a set is defined as [a, b], not
(a, b).
> SetCombined: TMyTypes = SetX + SetY; // this gives me an "Error:
> Illegal expression"
>
> I have been reading throught the FPC docs, but it is unclear whether
> this is possible at all. The set operators allow this and according
> to FPC doc section on constants some expression evaluation is
> possible.
So-called "typed constants" are actually initialised variables (for
historical reasons). The compiler cannot evaluate expressions that
involve variables (initialised or not).
Change the constants into symbol constants if you want to use them in
constant expressions:
const
SetX = [a, b];
SetY = [c, d];
SetCombined = SetX + SetY;
Jonas
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