# [fpc-devel] Division nodes

J. Gareth Moreton gareth at moreton-family.com
Sat May 20 00:16:39 CEST 2023

```That's useful to know - thanks Florian.  So it's possible to forego the
-1 check if no downsizing occurs.

I suppose it makes sense... if we go by the signed 64-bit equivalents,
\$FFFFFFFF80000000 div \$FFFFFFFFFFFFFFFF = \$0000000080000000, which when
typecast to a LongInt does result in a signed overflow that isn't
checked without -Co, so the answer is \$80000000.  On the flip side,
\$0000000080000000 div \$FFFFFFFFFFFFFFFF = \$FFFFFFFF80000000, which when
typecast to a LongInt is also equal to \$80000000, this time without an
overflow.  Even though the original operand of \$0000000080000000 is out
of range for a LongInt, it's perfectly fine as an Int64.

If my logic is correct, the -1 check is not needed in the following
conditions:

* The division is being upsized.
* There is no change in size and neither source is unsigned (e.g.
Cardinal --> LongInt would require the check).

Currently, as given in my original code example, LongInt(LongInt div
LongInt) is given the -1 check (assuming Integer = LongInt), and this
just seems like a waste.  Would you approve this change Florian? (I'll

Kit

----

On 19/05/2023 21:55, Florian Klämpfl via fpc-devel wrote:
> Am 19.05.23 um 21:14 schrieb J. Gareth Moreton via fpc-devel:
>> So I need to ask... should the check for a divisor of -1 still be
>> performed?
>
> Yes. This is the result of "down sizing" a division. In case of
>
> longint(int64 div int64) can be converted only into longint(int64) div
> longint(int64) if this check is carried out. longint(\$80000000 div
> \$ffffffff) must silently result in \$8000000 in this case.
>
>> The case of doing "min_int div -1", even with unsigned-to-signed
>> typecasting, seems very contrived and the programmer should expect
>> problems if "min_int" and "-1" appear as the operands.  Is there a
>> specific example where this implicit check is absolutely necessary?
>> As others have pointed out, silently returning "min_int" as the
>> answer seems more unexpected (granted this is just the behaviour of
>> an optimisation that converts the nodes equating to "x div -1" to
>> "-x", and Intel's NEG instruction doesn't return an error if min_int
>> is its input operand, but I can't be sure if the same applies to
>> non-Intel processors and their equivalent instructions).
>>
>> Kit
>>
>> On 17/05/2023 09:51, J. Gareth Moreton via fpc-devel wrote:
>>> Logically yes, but using 16-bit as an example, min_int is -32,768,
>>> and signed 16-bit integers range from -32,768 to 32,767. So -32,768
>>> ÷ -1 = 32,768, which is out of range.  This is where the problem lies.
>>>
>>> Internally, negation involves inverting all of the bits and then
>>> adding 1 (essentially how you subtract a number using two's
>>> complement), so min_int, which is 1000000000000000, becomes
>>> 0111111111111111 and then, after incrementing, 1000000000000000,
>>> which is min_int again.
>>>
>>> Kit
>>>
>>> On 16/05/2023 13:13, Jean SUZINEAU via fpc-devel wrote:
>>>> Le 16/05/2023 à 01:47, Stefan Glienke via fpc-devel a écrit :
>>>>> min_int div -1
>>>>
>>>> "min_int div -1"  should give  "- min_int" ?
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```