[fpc-devel] Optimization theory
J. Gareth Moreton
gareth at moreton-family.com
Mon Jun 25 05:57:33 CEST 2018
Of course, there's nothing to stop us from having a smaller table with an
actual hash, but that may give too much constant overhead, especially a
modulus operation.
Gareth aka. Kit
On Mon 25/06/18 04:23 , "J. Gareth Moreton" gareth at moreton-family.com
sent:
Actually you're right - that is the fastest method (it's written O(1), by
the way, if it doesn't depend on n). The drawback is that the large
majority of instructions don't have such an optimisation procedure, so the
table would be extremely sparse. There are 1,109 individual
instructions on x86 that FPC currently supports. Come to think of it,
even that is not too bad as far as memory goes - you're looking at 8,872
bytes on i386 (4 bytes for the instruction and 4 bytes for a pointer) and
17,744 bytes on x86-64 (8 bytes for each field), both are potentially
cacheable on the CPU hence won't be too costly in regards to looking it
up. Not sure why I overlooked that one. Thanks Martin.
Gareth aka. Kit
On Mon 25/06/18 00:18 , Martin fpc at mfriebe.de sent:
On 24/06/2018 23:28, J. Gareth Moreton wrote:
> On paper, a binary search is the fastest method to locate a data
> pointer associated with a key (in this case, an opcode).
Forgive me for stepping in, given that I hardly looked at your work, nor
the particular part of fpc.
But the fastest way should be a hash look up (O(n) = 1)
I might have missed something, so maybe I am completely out of line....
You have an enum. This could be used as a hash key (no need to
calculate, just take the raw value, and you have a perfect hash).
All you need to do is once build the hash table.
lookup = Array[tasmop] of CodePointer;
in unit initialization set the codepointer for the known opcodes.
Then you do not need to search. just
codepointer := lookup[taicpu(p).opcode]
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